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q$W�dS�(���ar��"Executable documentation" for the pickle module.

Extensive comments about the pickle protocols and pickle-machine opcodes
can be found here.  Some functions meant for external use:

genops(pickle)
   Generate all the opcodes in a pickle, as (opcode, arg, position) triples.

dis(pickle, out=None, memo=None, indentlevel=4)
   Print a symbolic disassembly of a pickle.
�����N�dis�genops�optimize���������������c���������������@���s���e�Zd�ZdZdd��ZdS�)�ArgumentDescriptor)�name�n�reader�docc�������������C���s`���t�|t�st�||�_t�|t�r8|dks<|ttttt	fks<t�||�_
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    ����r���z'not enough data in stream to read uint1N)�read�
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r&����uint1r!���zOne-byte unsigned integer.)r���r���r
���r���c�������������C���s0���|���d�}t|�dkr$td|�d�S�td��dS�)z�
    >>> import io
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    255
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    65535
    ����z<Hr���z'not enough data in stream to read uint2N)r"����len�_unpackr#���)r$���r%���r���r���r����
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r+����uint2r(���z)Two-byte unsigned integer, little-endian.c�������������C���s0���|���d�}t|�dkr$td|�d�S�td��dS�)z�
    >>> import io
    >>> read_int4(io.BytesIO(b'\xff\x00\x00\x00'))
    255
    >>> read_int4(io.BytesIO(b'\x00\x00\x00\x80')) == -(2**31)
    True
    ����z<ir���z&not enough data in stream to read int4N)r"���r)���r*���r#���)r$���r%���r���r���r����	read_int4����s����	
r.����int4r-���z8Four-byte signed integer, little-endian, 2's complement.c�������������C���s0���|���d�}t|�dkr$td|�d�S�td��dS�)z�
    >>> import io
    >>> read_uint4(io.BytesIO(b'\xff\x00\x00\x00'))
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    True
    r-���z<Ir���z'not enough data in stream to read uint4N)r"���r)���r*���r#���)r$���r%���r���r���r����
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r0����uint4z*Four-byte unsigned integer, little-endian.c�������������C���s0���|���d�}t|�dkr$td|�d�S�td��dS�)z�
    >>> import io
    >>> read_uint8(io.BytesIO(b'\xff\x00\x00\x00\x00\x00\x00\x00'))
    255
    >>> read_uint8(io.BytesIO(b'\xff' * 8)) == 2**64-1
    True
    ����z<Qr���z'not enough data in stream to read uint8N)r"���r)���r*���r#���)r$���r%���r���r���r����
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r3����uint8r2���z+Eight-byte unsigned integer, little-endian.Tc�������������C���s����|�����}|�d�std��|dd��}|rvxJdD�]6}|�|�r0|�|�sXtd||f���|dd��}P�q0W�td|���|r�t�|�d	��d
�}|S�)au��
    >>> import io
    >>> read_stringnl(io.BytesIO(b"'abcd'\nefg\n"))
    'abcd'

>>> read_stringnl(io.BytesIO(b"\n"))
    Traceback (most recent call last):
    ...
    ValueError: no string quotes around b''

>>> read_stringnl(io.BytesIO(b"\n"), stripquotes=False)
    ''

>>> read_stringnl(io.BytesIO(b"''\n"))
    ''

>>> read_stringnl(io.BytesIO(b'"abcd"'))
    Traceback (most recent call last):
    ...
    ValueError: no newline found when trying to read stringnl

Embedded escapes are undone in the result.
    >>> read_stringnl(io.BytesIO(br"'a\n\\b\x00c\td'" + b"\n'e'"))
    'a\n\\b\x00c\td'
    ����
z-no newline found when trying to read stringnlNr���)����"����'z,strinq quote %r not found at both ends of %rr!���zno string quotes around %rr����ascii)�readline�endswithr#����
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read_stringnl;��s ����

rA����stringnlz�A newline-terminated string.

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                   c�������������C���s���t�|�dd�S�)NF)r?���)rA���)r$���r���r���r����read_stringnl_noescapet��s����rC����stringnl_noescapea��A newline-terminated string.

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                        or bracketing quotes.  It should consist solely of
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                        c�������������C���s���dt�|��t�|��f�S�)zp
    >>> import io
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    'Queue Empty'
    z%s %s)rC���)r$���r���r���r����read_stringnl_noescape_pair���s����rE����stringnl_noescape_paira���A pair of newline-terminated strings.

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                             escapes, or bracketing quotes.  They should
                             consist solely of printable ASCII characters.
                             The pair is returned as a single string, with
                             a single blank separating the two strings.
                             c�������������C���sL���t�|��}|dkst�|��|�}t|�|kr4|�d�S�td|t|�f���dS�)z�
    >>> import io
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    r���zlatin-1z2expected %d bytes in a string1, but only %d remainN)r&���r���r"���r)���r>���r#���)r$���r���r%���r���r���r����read_string1���s����

rG����string1z�A counted string.

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              c�������������C���sT���t�|��}|dk�rtd|���|��|�}t|�|kr<|�d�S�td|t|�f���dS�)aP��
    >>> import io
    >>> read_string4(io.BytesIO(b"\x00\x00\x00\x00abc"))
    ''
    >>> read_string4(io.BytesIO(b"\x03\x00\x00\x00abcdef"))
    'abc'
    >>> read_string4(io.BytesIO(b"\x00\x00\x00\x03abcdef"))
    Traceback (most recent call last):
    ...
    ValueError: expected 50331648 bytes in a string4, but only 6 remain
    r���zstring4 byte count < 0: %dzlatin-1z2expected %d bytes in a string4, but only %d remainN)r.���r#���r"���r)���r>���)r$���r���r%���r���r���r����read_string4���s����

rI����string4z�A counted string.

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              the number of bytes in the string, and the second argument is
              that many bytes.
              c�������������C���sF���t�|��}|dkst�|��|�}t|�|kr.|S�td|t|�f���dS�)z�
    >>> import io
    >>> read_bytes1(io.BytesIO(b"\x00"))
    b''
    >>> read_bytes1(io.BytesIO(b"\x03abcdef"))
    b'abc'
    r���z1expected %d bytes in a bytes1, but only %d remainN)r&���r���r"���r)���r#���)r$���r���r%���r���r���r����read_bytes1���s����	
rK����bytes1z�A counted bytes string.

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              c�������������C���s\���t�|��}|dkst�|tjkr*td|���|��|�}t|�|krD|S�td|t|�f���dS�)aN��
    >>> import io
    >>> read_bytes4(io.BytesIO(b"\x00\x00\x00\x00abc"))
    b''
    >>> read_bytes4(io.BytesIO(b"\x03\x00\x00\x00abcdef"))
    b'abc'
    >>> read_bytes4(io.BytesIO(b"\x00\x00\x00\x03abcdef"))
    Traceback (most recent call last):
    ...
    ValueError: expected 50331648 bytes in a bytes4, but only 6 remain
    r���z#bytes4 byte count > sys.maxsize: %dz1expected %d bytes in a bytes4, but only %d remainN)r0���r����sys�maxsizer#���r"���r)���)r$���r���r%���r���r���r����read_bytes4���s����

rO����bytes4z�A counted bytes string.

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              c�������������C���s\���t�|��}|dkst�|tjkr*td|���|��|�}t|�|krD|S�td|t|�f���dS�)a���
    >>> import io, struct, sys
    >>> read_bytes8(io.BytesIO(b"\x00\x00\x00\x00\x00\x00\x00\x00abc"))
    b''
    >>> read_bytes8(io.BytesIO(b"\x03\x00\x00\x00\x00\x00\x00\x00abcdef"))
    b'abc'
    >>> bigsize8 = struct.pack("<Q", sys.maxsize//3)
    >>> read_bytes8(io.BytesIO(bigsize8 + b"abcdef"))  #doctest: +ELLIPSIS
    Traceback (most recent call last):
    ...
    ValueError: expected ... bytes in a bytes8, but only 6 remain
    r���z#bytes8 byte count > sys.maxsize: %dz1expected %d bytes in a bytes8, but only %d remainN)r3���r���rM���rN���r#���r"���r)���)r$���r���r%���r���r���r����read_bytes8��s����

rQ����bytes8z�A counted bytes string.

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              c�������������C���s0���|�����}|�d�std��|dd��}t|d�S�)zm
    >>> import io
    >>> read_unicodestringnl(io.BytesIO(b"abc\\uabcd\njunk")) == 'abc\uabcd'
    True
    r5���z4no newline found when trying to read unicodestringnlNr���zraw-unicode-escape)r9���r:���r#���r���)r$���r%���r���r���r����read_unicodestringnl8��s
����
rS����unicodestringnlz�A newline-terminated Unicode string.

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                      printable ASCII characters, and may contain embedded
                      escape sequences.
                      c�������������C���sN���t�|��}|dkst�|��|�}t|�|kr6t|dd�S�td|t|�f���dS�)a���
    >>> import io
    >>> s = 'abcd\uabcd'
    >>> enc = s.encode('utf-8')
    >>> enc
    b'abcd\xea\xaf\x8d'
    >>> n = bytes([len(enc)])  # little-endian 1-byte length
    >>> t = read_unicodestring1(io.BytesIO(n + enc + b'junk'))
    >>> s == t
    True

>>> read_unicodestring1(io.BytesIO(n + enc[:-1]))
    Traceback (most recent call last):
    ...
    ValueError: expected 7 bytes in a unicodestring1, but only 6 remain
    r���zutf-8�
surrogatepassz9expected %d bytes in a unicodestring1, but only %d remainN)r&���r���r"���r)���r���r#���)r$���r���r%���r���r���r����read_unicodestring1R��s����
rV����unicodestring1aA��A counted Unicode string.

The first argument is a 1-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    c�������������C���sd���t�|��}|dkst�|tjkr*td|���|��|�}t|�|krLt|dd�S�td|t|�f���dS�)a���
    >>> import io
    >>> s = 'abcd\uabcd'
    >>> enc = s.encode('utf-8')
    >>> enc
    b'abcd\xea\xaf\x8d'
    >>> n = bytes([len(enc), 0, 0, 0])  # little-endian 4-byte length
    >>> t = read_unicodestring4(io.BytesIO(n + enc + b'junk'))
    >>> s == t
    True

>>> read_unicodestring4(io.BytesIO(n + enc[:-1]))
    Traceback (most recent call last):
    ...
    ValueError: expected 7 bytes in a unicodestring4, but only 6 remain
    r���z+unicodestring4 byte count > sys.maxsize: %dzutf-8rU���z9expected %d bytes in a unicodestring4, but only %d remainN)r0���r���rM���rN���r#���r"���r)���r���)r$���r���r%���r���r���r����read_unicodestring4y��s����

rX����unicodestring4aA��A counted Unicode string.

The first argument is a 4-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    c�������������C���sd���t�|��}|dkst�|tjkr*td|���|��|�}t|�|krLt|dd�S�td|t|�f���dS�)a���
    >>> import io
    >>> s = 'abcd\uabcd'
    >>> enc = s.encode('utf-8')
    >>> enc
    b'abcd\xea\xaf\x8d'
    >>> n = bytes([len(enc)]) + b'\0' * 7  # little-endian 8-byte length
    >>> t = read_unicodestring8(io.BytesIO(n + enc + b'junk'))
    >>> s == t
    True

>>> read_unicodestring8(io.BytesIO(n + enc[:-1]))
    Traceback (most recent call last):
    ...
    ValueError: expected 7 bytes in a unicodestring8, but only 6 remain
    r���z+unicodestring8 byte count > sys.maxsize: %dzutf-8rU���z9expected %d bytes in a unicodestring8, but only %d remainN)r3���r���rM���rN���r#���r"���r)���r���)r$���r���r%���r���r���r����read_unicodestring8���s����

rZ����unicodestring8aB��A counted Unicode string.

The first argument is an 8-byte little-endian signed int
                    giving the number of bytes in the string, and the second
                    argument-- the UTF-8 encoding of the Unicode string --
                    contains that many bytes.
                    c�������������C���s.���t�|�ddd�}|dkrdS�|dkr&dS�t|�S�)z�
    >>> import io
    >>> read_decimalnl_short(io.BytesIO(b"1234\n56"))
    1234

>>> read_decimalnl_short(io.BytesIO(b"1234L\n56"))
    Traceback (most recent call last):
    ...
    ValueError: invalid literal for int() with base 10: b'1234L'
    F)r>���r?���s���00s���01T)rA���r���)r$����sr���r���r����read_decimalnl_short���s����r]���c�������������C���s2���t�|�ddd�}|dd��dkr*|dd��}t|�S�)z�
    >>> import io

>>> read_decimalnl_long(io.BytesIO(b"1234L\n56"))
    1234

>>> read_decimalnl_long(io.BytesIO(b"123456789012345678901234L\n6"))
    123456789012345678901234
    F)r>���r?���r���N����L)rA���r���)r$���r\���r���r���r����read_decimalnl_long���s����r_����decimalnl_shorta���A newline-terminated decimal integer literal.

This never has a trailing 'L', and the integer fit
                          in a short Python int on the box where the pickle
                          was written -- but there's no guarantee it will fit
                          in a short Python int on the box where the pickle
                          is read.
                          �decimalnl_longz�A newline-terminated decimal integer literal.

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                         of any size.
                         c�������������C���s���t�|�ddd�}t|�S�)zO
    >>> import io
    >>> read_floatnl(io.BytesIO(b"-1.25\n6"))
    -1.25
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In order to guarantee pickle interchangeability, the extension
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If not isinstance(callable, type), REDUCE complains unless the
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In addition, all the objects on the stack following the topmost
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Now it gets complicated.  If all of these are true:

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+ The class object does not have a __getinitargs__ attribute.

then we want to create an old-style class instance without invoking
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Else (the argtuple is not empty, it's not an old-style class object,
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Else (the class object does have a __safe_for_unpickling__ attr),
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This is the protocol 1 version of protocol 0's INST opcode, and is
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Unlike INST, OBJ takes no arguments from the opcode stream.  Instead
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Stack before: ... markobject classobject stackslice
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As for INST, the remainder of the stack above the markobject is
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NOTE:  In Python 2.3, INST and OBJ are identical except for how they
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The stack before should be thought of as containing a class
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The stack before should be thought of as containing a class
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For protocol 2 and above, a pickle must start with this opcode.
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Every pickle ends with this opcode.  The object at the top of the stack
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The unpickler may use this opcode to safely prefetch data from its
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    each opcode:

opcode, arg, pos

opcode is an OpcodeInfo record, describing the current opcode.

If the opcode has an argument embedded in the pickle, arg is its decoded
    value, as a Python object.  If the opcode doesn't have an argument, arg
    is None.

If the pickle has a tell() method, pos was the value of pickle.tell()
    before reading the current opcode.  If the pickle is a bytes object,
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��|�|��q4W�td||d��|�rttd|���dS�)aK��Produce a symbolic disassembly of a pickle.

'pickle' is a file-like object, or string, containing a (at least one)
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    the first STOP opcode encountered.

Optional arg 'out' is a file-like object to which the disassembly is
    printed.  It defaults to sys.stdout.

Optional arg 'memo' is a Python dict, used as the pickle's memo.  It
    may be mutated by dis(), if the pickle contains PUT or BINPUT opcodes.
    Passing the same memo object to another dis() call then allows disassembly
    to proceed across multiple pickles that were all created by the same
    pickler with the same memo.  Ordinarily you don't need to worry about this.

Optional arg 'indentlevel' is the number of blanks by which to indent
    a new MARK level.  It defaults to 4.

Optional arg 'annotate' if nonzero instructs dis() to add short
    description of the opcode on each line of disassembled output.
    The value given to 'annotate' must be an integer and is used as a
    hint for the column where annotation should start.  The default
    value is 0, meaning no annotations.

In addition to printing the disassembly, some sanity checks are made:

+ All embedded opcode arguments "make sense".

+ Explicit and implicit pop operations have enough items on the stack.

+ When an opcode implicitly refers to a markobject, a markobject is
      actually on the stack.

+ A memo entry isn't referenced before it's defined.

+ The markobject isn't stored in the memo.

+ A memo entry isn't redefined.
    Nr���� z%5d:)�end�filez	%-4s %s%sr!���r����z(MARK at unknown opcode offset)z(MARK at %d)r���zno MARK exists on stack)r����r����r����r����r����z(as %d)zmemo key %r already definedz'stack is empty -- can't store into memoz"can't store markobject in the memo)r����r����r����z&memo key %r has never been stored into�
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markobjectr���ry����pop�indexr#���r����splitr�����extend)r����r�����memo�indentlevel�annotate�stackZmaxprotoZ	markstackZindentchunkZerrormsgZannocolr����r|���r�����lineZbeforeZafterZnumtopopZmarkmsgZmarkposZmemo_idxr���r���r���r���
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c���������������@���s���e�Zd�Zdd��ZdS�)�_Examplec�������������C���s
���||�_�d�S�)N)�value)r���r��r���r���r���r����	��s����z_Example.__init__N)r���r���r���r���r���r���r���r���r���	��s���r��a���
>>> import pickle
>>> x = [1, 2, (3, 4), {b'abc': "def"}]
>>> pkl0 = pickle.dumps(x, 0)
>>> dis(pkl0)
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: I    INT        1
    8: a    APPEND
    9: I    INT        2
   12: a    APPEND
   13: (    MARK
   14: I        INT        3
   17: I        INT        4
   20: t        TUPLE      (MARK at 13)
   21: p    PUT        1
   24: a    APPEND
   25: (    MARK
   26: d        DICT       (MARK at 25)
   27: p    PUT        2
   30: c    GLOBAL     '_codecs encode'
   46: p    PUT        3
   49: (    MARK
   50: V        UNICODE    'abc'
   55: p        PUT        4
   58: V        UNICODE    'latin1'
   66: p        PUT        5
   69: t        TUPLE      (MARK at 49)
   70: p    PUT        6
   73: R    REDUCE
   74: p    PUT        7
   77: V    UNICODE    'def'
   82: p    PUT        8
   85: s    SETITEM
   86: a    APPEND
   87: .    STOP
highest protocol among opcodes = 0

Try again with a "binary" pickle.

>>> pkl1 = pickle.dumps(x, 1)
>>> dis(pkl1)
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: K        BININT1    1
    6: K        BININT1    2
    8: (        MARK
    9: K            BININT1    3
   11: K            BININT1    4
   13: t            TUPLE      (MARK at 8)
   14: q        BINPUT     1
   16: }        EMPTY_DICT
   17: q        BINPUT     2
   19: c        GLOBAL     '_codecs encode'
   35: q        BINPUT     3
   37: (        MARK
   38: X            BINUNICODE 'abc'
   46: q            BINPUT     4
   48: X            BINUNICODE 'latin1'
   59: q            BINPUT     5
   61: t            TUPLE      (MARK at 37)
   62: q        BINPUT     6
   64: R        REDUCE
   65: q        BINPUT     7
   67: X        BINUNICODE 'def'
   75: q        BINPUT     8
   77: s        SETITEM
   78: e        APPENDS    (MARK at 3)
   79: .    STOP
highest protocol among opcodes = 1

Exercise the INST/OBJ/BUILD family.

>>> import pickletools
>>> dis(pickle.dumps(pickletools.dis, 0))
    0: c    GLOBAL     'pickletools dis'
   17: p    PUT        0
   20: .    STOP
highest protocol among opcodes = 0

>>> from pickletools import _Example
>>> x = [_Example(42)] * 2
>>> dis(pickle.dumps(x, 0))
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: c    GLOBAL     'copy_reg _reconstructor'
   30: p    PUT        1
   33: (    MARK
   34: c        GLOBAL     'pickletools _Example'
   56: p        PUT        2
   59: c        GLOBAL     '__builtin__ object'
   79: p        PUT        3
   82: N        NONE
   83: t        TUPLE      (MARK at 33)
   84: p    PUT        4
   87: R    REDUCE
   88: p    PUT        5
   91: (    MARK
   92: d        DICT       (MARK at 91)
   93: p    PUT        6
   96: V    UNICODE    'value'
  103: p    PUT        7
  106: I    INT        42
  110: s    SETITEM
  111: b    BUILD
  112: a    APPEND
  113: g    GET        5
  116: a    APPEND
  117: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(x, 1))
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: c        GLOBAL     'copy_reg _reconstructor'
   29: q        BINPUT     1
   31: (        MARK
   32: c            GLOBAL     'pickletools _Example'
   54: q            BINPUT     2
   56: c            GLOBAL     '__builtin__ object'
   76: q            BINPUT     3
   78: N            NONE
   79: t            TUPLE      (MARK at 31)
   80: q        BINPUT     4
   82: R        REDUCE
   83: q        BINPUT     5
   85: }        EMPTY_DICT
   86: q        BINPUT     6
   88: X        BINUNICODE 'value'
   98: q        BINPUT     7
  100: K        BININT1    42
  102: s        SETITEM
  103: b        BUILD
  104: h        BINGET     5
  106: e        APPENDS    (MARK at 3)
  107: .    STOP
highest protocol among opcodes = 1

Try "the canonical" recursive-object test.

>>> L = []
>>> T = L,
>>> L.append(T)
>>> L[0] is T
True
>>> T[0] is L
True
>>> L[0][0] is L
True
>>> T[0][0] is T
True
>>> dis(pickle.dumps(L, 0))
    0: (    MARK
    1: l        LIST       (MARK at 0)
    2: p    PUT        0
    5: (    MARK
    6: g        GET        0
    9: t        TUPLE      (MARK at 5)
   10: p    PUT        1
   13: a    APPEND
   14: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(L, 1))
    0: ]    EMPTY_LIST
    1: q    BINPUT     0
    3: (    MARK
    4: h        BINGET     0
    6: t        TUPLE      (MARK at 3)
    7: q    BINPUT     1
    9: a    APPEND
   10: .    STOP
highest protocol among opcodes = 1

Note that, in the protocol 0 pickle of the recursive tuple, the disassembler
has to emulate the stack in order to realize that the POP opcode at 16 gets
rid of the MARK at 0.

>>> dis(pickle.dumps(T, 0))
    0: (    MARK
    1: (        MARK
    2: l            LIST       (MARK at 1)
    3: p        PUT        0
    6: (        MARK
    7: g            GET        0
   10: t            TUPLE      (MARK at 6)
   11: p        PUT        1
   14: a        APPEND
   15: 0        POP
   16: 0        POP        (MARK at 0)
   17: g    GET        1
   20: .    STOP
highest protocol among opcodes = 0

>>> dis(pickle.dumps(T, 1))
    0: (    MARK
    1: ]        EMPTY_LIST
    2: q        BINPUT     0
    4: (        MARK
    5: h            BINGET     0
    7: t            TUPLE      (MARK at 4)
    8: q        BINPUT     1
   10: a        APPEND
   11: 1        POP_MARK   (MARK at 0)
   12: h    BINGET     1
   14: .    STOP
highest protocol among opcodes = 1

Try protocol 2.

>>> dis(pickle.dumps(L, 2))
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: h    BINGET     0
    7: \x85 TUPLE1
    8: q    BINPUT     1
   10: a    APPEND
   11: .    STOP
highest protocol among opcodes = 2

>>> dis(pickle.dumps(T, 2))
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: h    BINGET     0
    7: \x85 TUPLE1
    8: q    BINPUT     1
   10: a    APPEND
   11: 0    POP
   12: h    BINGET     1
   14: .    STOP
highest protocol among opcodes = 2

Try protocol 3 with annotations:

>>> dis(pickle.dumps(T, 3), annotate=1)
    0: \x80 PROTO      3 Protocol version indicator.
    2: ]    EMPTY_LIST   Push an empty list.
    3: q    BINPUT     0 Store the stack top into the memo.  The stack is not popped.
    5: h    BINGET     0 Read an object from the memo and push it on the stack.
    7: \x85 TUPLE1       Build a one-tuple out of the topmost item on the stack.
    8: q    BINPUT     1 Store the stack top into the memo.  The stack is not popped.
   10: a    APPEND       Append an object to a list.
   11: 0    POP          Discard the top stack item, shrinking the stack by one item.
   12: h    BINGET     1 Read an object from the memo and push it on the stack.
   14: .    STOP         Stop the unpickling machine.
highest protocol among opcodes = 2

a=��
>>> import pickle
>>> import io
>>> f = io.BytesIO()
>>> p = pickle.Pickler(f, 2)
>>> x = [1, 2, 3]
>>> p.dump(x)
>>> p.dump(x)
>>> f.seek(0)
0
>>> memo = {}
>>> dis(f, memo=memo)
    0: \x80 PROTO      2
    2: ]    EMPTY_LIST
    3: q    BINPUT     0
    5: (    MARK
    6: K        BININT1    1
    8: K        BININT1    2
   10: K        BININT1    3
   12: e        APPENDS    (MARK at 5)
   13: .    STOP
highest protocol among opcodes = 2
>>> dis(f, memo=memo)
   14: \x80 PROTO      2
   16: h    BINGET     0
   18: .    STOP
highest protocol among opcodes = 2
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